Diode Calculator

Size the current-limiting resistor, or find the forward current and power dissipation of any diode.
Series Resistor
Current & Power

Current-Limiting Resistor for a Diode

R = (Vsupply − VF) / I  •  Pdiode = VF × I  •  Presistor = (Vsupply − VF) × I
5V, Si 0.7V, 20mA
12V, Si 0.7V, 50mA
5V, Schottky 0.3V
5V, LED 2.0V
V
V
mA
Enter values and press Calculate.

Diode Forward Current & Power

IF = (Vsupply − VF) / R  •  Pdiode = VF × IF  •  Presistor = IF² × R
12V, 0.7V, 330Ω
5V, Schottky, 150Ω
9V, LED, 470Ω
V
V
Ω
Enter values and press Calculate.

Understanding Diode Calculations

A diode conducts in the forward direction after its forward voltage drop (VF) is reached — roughly 0.7 V for silicon, 0.3 V for Schottky, and 1.8–3.6 V for LEDs. To run a fixed current through it from a higher supply, a series resistor drops the remaining voltage.

QuantityFormula
Series resistorR = (Vsupply − VF) / IF
Forward currentIF = (Vsupply − VF) / R
Diode powerPdiode = VF × IF
Resistor powerPresistor = IF² × R

Typical forward voltages

Silicon signal/rectifier ≈ 0.7 V · Schottky ≈ 0.2–0.4 V · Germanium ≈ 0.3 V · Red LED ≈ 1.8–2.0 V · Blue/White LED ≈ 3.0–3.6 V.

Real-World Applications

Worked example

Driving a 20 mA indicator LED (VF = 2.0 V) from a 5 V rail:
R = (5 − 2.0) / 0.020 = 150 Ω. The LED dissipates 2.0 × 20 mA = 40 mW and the resistor 3.0 × 20 mA = 60 mW, so a standard ¼ W resistor is fine.

FAQ

Schottky or silicon — which should I use?

Schottky diodes have a lower forward drop (~0.3 V) and switch faster, so they waste less power — ideal for rectifiers and low-voltage circuits. Silicon (like the 1N4007) is cheaper and handles higher reverse voltage.

What is PIV / reverse voltage rating?

Peak Inverse Voltage is the maximum reverse voltage a diode can block without breaking down. Always pick a diode rated well above the highest reverse voltage in your circuit.

Why does my diode get hot?

It dissipates VF × IF as heat. At high current even a 0.7 V drop adds up — e.g. 3 A gives ~2 W. Use a Schottky or a heat-sinked diode for high-current rectification.

Can I put diodes in series or parallel?

In series their voltage drops add. In parallel they share current unevenly (the one with the lowest VF hogs it), so parallel diodes usually need small balancing resistors.

Why does a diode need a series resistor?

A forward-biased diode has very low resistance, so without a series resistor the current would rise until the diode overheats and fails. The resistor sets a safe, defined current.

What forward voltage should I use?

Check the datasheet at your operating current. As a rule of thumb: 0.7 V silicon, 0.3 V Schottky, ~2 V red LED, ~3.2 V blue/white LED.

How do I choose the resistor's wattage?

Use Presistor from the result and pick a resistor rated at least 2× that value for a safe margin.

Frequently Asked Questions

What is the forward voltage of a diode?

About 0.7 V for silicon, 0.3 V for germanium, and 0.2–0.5 V for Schottky types. It rises slowly with current and falls roughly 2 mV per °C as temperature increases.

How much power does a diode dissipate?

Approximately Vf × Iavg for conduction loss. A 1 A rectifier at 0.7 V dissipates about 0.7 W, which is why Schottky diodes are preferred in low-voltage supplies where that drop is a large fraction of the output.

What is reverse recovery and when does it matter?

The brief period after a diode is reverse-biased during which it still conducts while stored charge is swept out. At mains frequency it is irrelevant; in a switching converter it causes loss and EMI, which is why fast or ultrafast recovery types are specified.

Why do Schottky diodes have higher leakage?

Their lower forward voltage comes from a metal-semiconductor junction with a lower barrier height, which also permits more reverse leakage. Leakage roughly doubles every 10 °C, so at high temperature it can become a significant loss in itself.

How should I choose the reverse voltage rating?

With generous margin — commonly at least twice the expected peak reverse voltage. Switching transients and inductive ringing routinely exceed the nominal value, and exceeding the rating destroys the device.

Does a diode's forward voltage change with temperature?

Yes, falling about 2 mV per °C. That predictable drift is the basis of diode-based temperature sensing, but it also means a hot diode draws a larger share of current when paralleled, which is why paralleled diodes need ballast resistors.

Diode & Rectifier Parts