Inverter Modulation Index Calculator

Fundamental output voltage of an SPWM inverter from the DC bus and amplitude modulation ratio ma.
Modulation Index → Vout

SPWM Fundamental Output

Full-bridge 1φ: V1(rms) = ma × Vdc / √2  (ma ≤ 1)
1φ FB, 400V, m=0.8
3φ, 700V, m=0.9
3φ, 700V, m=1.0
V
Enter values and press Calculate.

Modulation Index & Inverter Output

An inverter turns DC into AC by switching. In sinusoidal PWM (SPWM) a sine reference is compared with a triangular carrier; the amplitude modulation ratio ma is the ratio of the sine peak to the carrier peak. In the linear region (ma ≤ 1) the fundamental output voltage is directly proportional to ma, which is how the inverter (or VFD) controls the AC voltage.

InverterFundamental output (ma ≤ 1)
1φ Half-bridgeV1(peak) = ma·Vdc/2  →  V1(rms) = ma·Vdc/(2√2)
1φ Full-bridgeV1(peak) = ma·Vdc  →  V1(rms) = ma·Vdc/√2
3φ (line-to-line RMS)VLL(rms) = ma·(√3/(2√2))·Vdc = 0.612·ma·Vdc

Above ma = 1 the inverter enters overmodulation; the output keeps rising but no longer linearly, and low-order harmonics appear. The limit is the six-step (square-wave) mode, where the single-phase full bridge reaches (4/π)·Vdc/√2 ≈ 0.90·Vdc RMS and the three-phase line-to-line RMS reaches 0.78·Vdc.

Real-World Applications & Examples

Worked examples

1. 1φ full-bridge, 400 V, ma=0.8. V1(rms)=0.8×400/√2=226.3 V.
2. At ma=1.0. V1(rms)=1.0×400/√2=282.8 V — the top of the linear range.
3. 3φ inverter, 700 V bus, ma=0.9. VLL(rms)=0.612×0.9×700=385.6 V — close to a 400 V grid.
4. Half-bridge, 400 V, ma=1. V1(rms)=1×400/(2√2)=141.4 V — half the full-bridge output.
5. Six-step limit (1φ FB). Square-wave output = (4/π)×400/√2=360.1 V RMS, the absolute maximum fundamental.
6. Sizing the DC bus. To feed a 400 V 3φ motor at ma=0.9 you need Vdc=400/(0.612×0.9)≈726 V, which is why 700–750 V buses are common.

Modulation Index, the Linear Region, and Overmodulation

In sinusoidal PWM, the modulation index is the ratio of the reference (control) waveform amplitude to the triangular carrier amplitude:

m = Vcontrol / Vcarrier

The duty cycle of a half-bridge then follows d(t) = ½(1 + m sin ωt). At m = 0.8, duty swings between 0.1 and 0.9 across the fundamental cycle, sitting at 0.5 at each zero crossing.

Why m ≤ 1 is the useful region

While m stays at or below 1 the output fundamental is linearly proportional to m, and the switching harmonics sit in a tidy cluster around the carrier frequency where a modest output filter removes them easily. This predictability is the entire appeal of PWM.

Push m above 1 and the reference exceeds the carrier peak, so for part of the cycle there is no crossing at all and the leg simply saturates to one rail. Fundamental output keeps rising, but no longer in proportion, and low-order harmonics — the fifth, seventh and so on — appear in the output. Those are much harder to filter than the carrier-frequency cluster, because they sit close to the fundamental. At the extreme the modulator degenerates into six-step square-wave operation, which gives the maximum possible fundamental at the cost of the worst harmonic spectrum.

Third-harmonic injection: more output for free

A three-phase inverter can do better than m = 1. Adding a third-harmonic component to the reference flattens its peaks without changing the line-to-line output, because third harmonics are identical in all three phases and cancel in the line-to-line difference. This allows the modulation index to reach 2/√3 ≈ 1.155 while still operating linearly — roughly 15% more output voltage from the same DC link, at no cost in harmonic quality. Space-vector modulation achieves the same ceiling by a different route and is the usual choice in modern drives.

Frequently Asked Questions

What is the modulation index of an inverter?

The amplitude modulation ratio ma is the ratio of the peak of the sinusoidal reference to the peak of the triangular carrier in SPWM. It directly scales the fundamental output voltage in the linear region (ma ≤ 1).

How does modulation index affect output voltage?

In the linear region the fundamental output is proportional to ma. For a single-phase full bridge V1(rms)=ma·Vdc/√2, so doubling ma doubles the output (up to ma=1).

What is the linear modulation range?

It is 0 ≤ ma ≤ 1. Within this range the output rises linearly with ma and the harmonics stay near the switching frequency, making them easy to filter.

What is overmodulation?

When ma > 1 the reference exceeds the carrier for part of the cycle, so the output stops rising linearly and low-order harmonics appear. It boosts the fundamental beyond the linear limit at the cost of distortion.

What is the maximum inverter output voltage?

The absolute maximum is the six-step (square-wave) mode: for a single-phase full bridge (4/π)·Vdc/√2 ≈ 0.90·Vdc RMS, and for a three-phase inverter 0.78·Vdc line-to-line RMS.

Why is the three-phase factor 0.612?

For SPWM the phase peak is ma·Vdc/2. The line-to-line value is √3 times the phase, and RMS divides the peak by √2, giving √3/(2√2)=0.612 times ma·Vdc.

What is the difference between half-bridge and full-bridge output?

A full bridge applies the whole DC bus across the load and gives twice the output of a half bridge, which only swings between +Vdc/2 and −Vdc/2. Hence the full-bridge fundamental is ma·Vdc/√2 versus ma·Vdc/(2√2).

What is the frequency modulation ratio mf?

mf = fcarrier/foutput is the ratio of the switching (carrier) frequency to the output frequency. A high, odd, integer mf pushes harmonics to high frequencies and keeps the waveform symmetric.

How do I size the DC bus for a given AC output?

Rearrange the formula. For a three-phase inverter, Vdc = VLL(rms)/(0.612·ma). Designers usually pick ma around 0.85–0.95 to leave margin, which sets the required bus voltage.

Does space-vector PWM give more output?

Yes. Space-vector modulation (SVPWM) uses the bus about 15% more effectively than basic SPWM, reaching a line-to-line RMS of roughly 0.707·Vdc at the edge of the linear region versus 0.612·Vdc for SPWM.

How does modulation index relate to VFD speed control?

A VFD keeps a constant volts-per-hertz ratio, so as it raises the output frequency it raises ma to raise the voltage, until ma reaches its limit at base speed. Above that, the motor runs in the field-weakening (constant-power) region.

What output does ma = 0 give?

Zero fundamental output. With no reference signal the inverter produces equal positive and negative pulses that average to zero, so no net AC voltage appears at the output.

What is the modulation index?

The ratio of the control (reference) waveform amplitude to the carrier waveform amplitude in a PWM modulator. It sets how much of the available DC-link voltage appears in the output fundamental.

What is the linear modulation range?

m ≤ 1 for plain sinusoidal PWM. Within it, output fundamental voltage is directly proportional to m and the switching harmonics stay clustered around the carrier frequency, where they are easy to filter.

What happens during overmodulation?

The reference exceeds the carrier peak, so parts of the cycle have no crossings and the leg clamps to a rail. Output keeps rising but non-linearly, and low-order harmonics such as the fifth and seventh appear, which are far harder to filter.

What is third-harmonic injection?

Adding a third-harmonic component to the reference waveform to flatten its peaks. Because third harmonics are identical in all three phases, they cancel in the line-to-line output, so the modulation index can reach about 1.155 while remaining linear.

How much extra output does third-harmonic injection give?

About 15%, since the usable modulation index rises from 1 to 2/√3 ≈ 1.155. Space-vector modulation reaches the same limit by a different method.

How does the carrier frequency affect the design?

A higher carrier pushes switching harmonics further from the fundamental, so the output filter can be smaller. The cost is higher switching loss in the devices, which is the usual trade-off between filter size and efficiency.

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