Note: The RMS meter shows the effective (heating) value of AC voltage.
Note: The RMS meter shows the effective (heating) value of AC voltage.
Waveform Visualization: Real-time display of selected waveform with RMS indication.
| Parameter | Value | Unit |
|---|---|---|
| AC RMS Input | - | V |
| DC Output | - | V |
| Peak Voltage | - | V |
| Ripple Factor | - | % |
| Power (if current given) | - | W |
Note: Values assume ideal components. Real circuits may have additional losses.
| Parameter | Value |
|---|---|
| Total RMS | - |
| THD (%) | - |
| Crest Factor | - |
| Form Factor | - |
Root Mean Square (RMS) voltage is the effective value of an AC voltage that produces the same heating effect as an equivalent DC voltage. It's calculated as the square root of the mean of the squares of instantaneous values.
Standard US household voltage has a peak of 170V. What is the RMS voltage?
Solution: VRMS = 170 / √2 = 170 / 1.414 = 120.2 V
A square wave oscillates between +15V and -15V. What is the RMS voltage?
Solution: For square waves, VRMS = Vpeak = 15 V
A triangle wave has a peak voltage of 24V. Calculate the RMS voltage.
Solution: VRMS = 24 / √3 = 24 / 1.732 = 13.86 V
A distorted sine wave has: Fundamental = 100V, 3rd harmonic = 20V, 5th harmonic = 10V. Find total RMS.
Solution: VRMS = √(100² + 20² + 10²) = √(10000 + 400 + 100) = 102.47 V
RMS stands for root mean square, and the name is a literal recipe: square the waveform, take the mean of those squares, then take the square root. The reason for that apparently odd procedure is that heating depends on the square of voltage, so squaring first is what makes the result physically meaningful.
The RMS value of an AC waveform is the DC voltage that would produce the same heating in a resistor. That is why mains is described as 230 V even though its instantaneous voltage spends most of the cycle somewhere else entirely, and why a 230 V RMS supply and a 230 V DC supply deliver identical power to a heater.
The arithmetic mean of a symmetrical sine wave is zero, since the negative half cancels the positive. A measure that reports zero for a supply capable of electrocution is not a useful one — which is precisely why RMS exists.
For a sine, VRMS = Vpeak/√2, so nominal 230 V mains peaks at about 325 V. This relationship is specific to the sine shape, and applying it to anything else gives the wrong answer:
| Waveform | VRMS relative to peak |
|---|---|
| Sine | 0.707 × Vpeak |
| Square (symmetrical) | 1.000 × Vpeak |
| Triangle / sawtooth | 0.577 × Vpeak |
Cheap meters rectify the signal, measure its average, and multiply by 1.11 — the form factor that converts average to RMS for a sine wave. On a distorted waveform, such as the current drawn by a switch-mode supply or the output of a phase-angle dimmer, that assumption fails and the reading is wrong, usually low. A true-RMS instrument performs the actual squaring and averaging, and is essential anywhere electronic loads are involved.
Root mean square: square the waveform, average the squares, then take the square root. The result is the equivalent DC voltage that would produce the same heating in a resistor.
Because the average of a symmetrical AC waveform is zero, which tells you nothing. Heating depends on voltage squared, so squaring before averaging is what makes the figure physically meaningful.
About 325 V, since peak equals RMS times √2 for a sine wave. Insulation and semiconductor ratings must withstand that peak.
No, only to sine waves. A symmetrical square wave has an RMS value equal to its peak, and a triangle wave about 0.577 of its peak.
Because averaging meters assume a sine wave and apply a fixed 1.11 form factor. On distorted waveforms such as switch-mode supply current or dimmer output they read incorrectly, usually low.
The concept is identical and both are defined the same way. Power is the product of RMS voltage and RMS current only when they are in phase; otherwise the power factor must also be applied.